Let's see if this time I have dropping fuel pressure
#1
Thread Starter
Joined: Jun 2005
Posts: 4,515
Likes: 242
From: Suburban Chicago
3 Denso 1020s

This is going to take awhile, I'm just collecting parts now. It will be a surge tank. One pump will run constantly, and the other two will be boost-activated. They all will be wired separately so I can disable the third, and maybe the second if I have to, until I can afford E85-capable injectors.

This is going to take awhile, I'm just collecting parts now. It will be a surge tank. One pump will run constantly, and the other two will be boost-activated. They all will be wired separately so I can disable the third, and maybe the second if I have to, until I can afford E85-capable injectors.
#5
Joined: Jan 2006
Posts: 16,282
Likes: 438
From: Huntsville, AL
I believe the output of the 1020 is 5/16...that being the case I wouldve wanted something bigger like 5/8ths or 3/4 for the merged single output, just for the shear volume of fuel 3 of these pumps could move.
#7
Joined: Jan 2006
Posts: 16,282
Likes: 438
From: Huntsville, AL
ah, should be fine then.....what fuel filter are you using? How big of a surge tank are you using?
If I did my math right, 3 of those pumps can drain a 1 gallon tank in about 20 seconds assuming your FP is around 65psi, faster if its lower obviously. The physical pumps will take up quite a bit of room in the tank (displacing fuel), so it will actually not hold a full gallon and will be "empty" much sooner. By my measurements the pumps will displace about 0.16 gallons in the tank so your 20 seconds turned into 16 seconds. Taking this further, the pump socks will have to be fully submerged in fuel otherwise they are sucking air, so lets say there is at least 15% minimum useful fuel level, so now we are down to 13.5 seconds...
Just food for thought...
If I did my math right, 3 of those pumps can drain a 1 gallon tank in about 20 seconds assuming your FP is around 65psi, faster if its lower obviously. The physical pumps will take up quite a bit of room in the tank (displacing fuel), so it will actually not hold a full gallon and will be "empty" much sooner. By my measurements the pumps will displace about 0.16 gallons in the tank so your 20 seconds turned into 16 seconds. Taking this further, the pump socks will have to be fully submerged in fuel otherwise they are sucking air, so lets say there is at least 15% minimum useful fuel level, so now we are down to 13.5 seconds...
Just food for thought...
Last edited by Atomic; Oct 3, 2011 at 09:17 PM.
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#9
Lol...Next your next thread gonna say somthin like "I hydrolocked my Whippled 408 wat I do now???
Lets hope im wrong.Hopefully its gonna say "I got traction woes cause,my Whippled 408 makes a buzzillion rwhp".Hmm...Well not a buzzillion maybe 500-600rwhp would be more realistic.Still with traction woes though.
Lets hope im wrong.Hopefully its gonna say "I got traction woes cause,my Whippled 408 makes a buzzillion rwhp".Hmm...Well not a buzzillion maybe 500-600rwhp would be more realistic.Still with traction woes though.
#10
Thread Starter
Joined: Jun 2005
Posts: 4,515
Likes: 242
From: Suburban Chicago
The tank will be just over six gallons, ...
so 13.5 x 6 = 81.6 seconds, or 1 min. 21.6 sec. Using a conservative 0-60 mph time of 6 seconds, from lack of traction, I divide that into one full minute of WOT, and I figure I will be doing right about 600 mph, at which point I would probably let off the throttle. So I probably wouldn't need the extra 21.6 seconds of fuel in the surge tank.
so 13.5 x 6 = 81.6 seconds, or 1 min. 21.6 sec. Using a conservative 0-60 mph time of 6 seconds, from lack of traction, I divide that into one full minute of WOT, and I figure I will be doing right about 600 mph, at which point I would probably let off the throttle. So I probably wouldn't need the extra 21.6 seconds of fuel in the surge tank.







