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g forces

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Old Feb 9, 2007 | 10:25 AM
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ok i have a good one here. if you have say a pendulum hanging from your rear view and you go into a turn at one "g" where will the pendulum lie in degrees of an angle? i say it will sit a 90* angle and a guy at work says it will sit at a 45* angle. what do you think and why?
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Old Feb 9, 2007 | 12:30 PM
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I think it would be at 45 degrees because your have 1 G of side acceleration and 1 G of downward acceleration. 1/1 = 1 and inverse tangent of 1 is 45 degrees.
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Old Feb 9, 2007 | 02:03 PM
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also the wieght of the pendulum
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Old Feb 9, 2007 | 02:37 PM
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Originally Posted by alanderson1978
I think it would be at 45 degrees because your have 1 G of side acceleration and 1 G of downward acceleration. 1/1 = 1 and inverse tangent of 1 is 45 degrees.


The only way you'd get it to go 90* is if you removed the downward acceleration of gravity.
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Old Feb 9, 2007 | 02:40 PM
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Weight would have nothing to do with it. G's is constant on an object regardless of weight.

It would sit at a 45 degree angle. A perfect 90 degree angle would very high in g-force due to that constant 1G pulling it down very slightly. A 85+ degree angle would be around 3G's(guessing, because I don't want to do the math)
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Old Feb 9, 2007 | 02:44 PM
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45*
Like stated above G=gravity
1G is a standard force we feel sitting still, so if you took a turn to the right and it's lateral force was + 1G then you would have 1G in two directions, 90* apart, putting the pendulum in the middle of 2 equal forces = 45*
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Old Feb 9, 2007 | 02:49 PM
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then can someone explain to me how my cousins civic hatchback use to be able to get the necklace hanging in his rearview to over 45*. when i was 16 we use to take his hatch down the mountian we lived on and hit the 25 mph curves at about 55-60 sometimes more. and we would try to get it to go 90 and never could and we thought that 90 would be a full g. and i don't mean we would cut the car real fast and it would swing up i mean around the long winding curves it would sit at least a 45*. i wouldn't think the hatch could hit a g let alone go over it. now the curves were at angles kinda like nascar tracks but not to the extent. i personally never thought about the weight pushing down on it. maybe they were just well built curves because my lowered s-10 could get the it to swing to atleast 40* but it did handle real well. the rednecks that didn't like my low rider would try to chase me up the moutain in there big 4x4's and the small blocks could catch my 2.8 on the striaght but time for corners and i was gone. being that this is going in a circle wouldn't centrifigul force come into play also how do g force and centrifigul force correlate?
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Old Feb 9, 2007 | 11:53 PM
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2 G's would put it at about 63.5*
3 G's about 71.5*
You would need a fighter jet to get the 11.4 G's required to hit 85*

Did you measure the angles or eyeball it? Angles are hard for most to guess accurately.
Since the turn was banked, was it 45* to true perpendicular or 45* to perpendicular of the road?
I can't really give you any formulas for this, it's been 10 years since I had a Physics class, but work makes me keep my geometry/algebra/trig pretty sharp

If you were swinging on that pendulum during a 1 G turn, you would not feel any force to the side, but you would feel about 40% heavier.

If I had some free time I would try some of this out myself.

Knowledge is power!!!
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Old Feb 10, 2007 | 08:34 AM
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i was 15-16 years old i eye balled it. i didn't realize it took so much to get a 90* angle. hhmmmm ok so how does a swinging motion differ from a g force motion? i'm always up to learn something new.
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Old Feb 10, 2007 | 10:29 AM
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I wish I knew a bit more about centrifugal/centripital forces. I haven't used a lot of my Physics knowledge so I've lost some of it

You will never be able to get to 90* as long as there is gravity. The G forces rise exponentially as the angle rises in this case. As the angle approaches 90*, the G force will approach infinity. My tires aren't good enough to do that
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