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radix pulley flow

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Old Nov 16, 2008 | 02:17 AM
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Default radix pulley flow

Does this make sense

For a given radix pullet size.. does it makes sense that the engine should make the same power? If for a fixed pulley size the blower spins x rpm. which means it flows x cfm.. which regardless of the engine size, should equal x hp or am i completely off my rocker??
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Old Nov 16, 2008 | 10:13 AM
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You are correct but threre are some variables. If you can move X amount of air then you have potential to make X amount of power even with different size engines. To fit a large amount of air through a smaller engine you would need to spin it faster or end up with more boost. The power will vary between engines depending on how efficient each can use that amount of air. In the case of the Radix, it may not be as efficient running a 12psi through a 4.8 compared to 8 psi through a 6.0L.
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Old Nov 16, 2008 | 10:46 AM
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Hell Yeah!

So for a given blower rpm the amount of air pumped will be constant but the engine's efficiency will determine horsepower output.
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Old Nov 16, 2008 | 10:53 AM
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Originally Posted by trever1t
Hell Yeah!

So for a given blower rpm the amount of air pumped will be constant but the engine's efficiency will determine horsepower output.
yep
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Old Nov 16, 2008 | 12:30 PM
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Right i was thinking that to push the same amount of air through the smaller motor the blower has to fight the increased pressure to pump more air.. does this also heat up the air a bit more?
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Old Nov 17, 2008 | 11:52 AM
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Originally Posted by PSM
Right i was thinking that to push the same amount of air through the smaller motor the blower has to fight the increased pressure to pump more air.. does this also heat up the air a bit more?
That will be the single biggest problem. X+1lbs on a 4.8L might generate way too much heat to allow for the theoretical equivilent of X-1lbs on a 6L. That said if u can keep it cool via meth or larger exchanger with bigger/more flow, or even ice the ur limiting factor becomes injector, cam, compression, heads...etc.
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