Forced induction = what displacement?
#1
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13 Second Truck Club
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Joined: Nov 2006
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From: Hartland, MI
Been curious about this for a while now so from what I found on the Internet does this sound correct ?
using this equation...
9 psi + 14.7 = 23.7
23.7/14.7 = 1.61
1.61x 5.3 = 8.5L
just seems weird
using this equation...
9 psi + 14.7 = 23.7
23.7/14.7 = 1.61
1.61x 5.3 = 8.5L
just seems weird
#6
Thread Starter
13 Second Truck Club
iTrader: (7)
Joined: Nov 2006
Posts: 874
Likes: 13
From: Hartland, MI
just came across a forum that was saying that so many pounds of boost does X amount to your displacement. They also had their equations how to break it down to how much horsepower that is over baseline. Figured I'd ask a question on this forum seeing that I'm on here almost every day. It was it just a thought to ask. I understand there's other variables on the situation I was just seeing if anybody has figured it out.
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#8
just came across a forum that was saying that so many pounds of boost does X amount to your displacement. They also had their equations how to break it down to how much horsepower that is over baseline. Figured I'd ask a question on this forum seeing that I'm on here almost every day. It was it just a thought to ask. I understand there's other variables on the situation I was just seeing if anybody has figured it out.
Since psi is just resistance to flow.
The simple math I listed is solid comparing cubic inches.
But just because you double cubes does not mean you double HP.


